Table: Weather
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| id | int |
| recordDate | date |
| temperature | int |
+---------------+---------+
id is the primary key for this table.
This table contains information about the temperature in a certain day.
Write an SQL query to find all dates' id with higher temperature compared to its previous dates (yesterday).
Return the result table in any order.
The query result format is in the following example:
Weather
+----+------------+-------------+
| id | recordDate | Temperature |
+----+------------+-------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+----+------------+-------------+
Result table:
+----+
| id |
+----+
| 2 |
| 4 |
Solution:
select distinct w2.id from Weather w1
inner join Weather w2
on w1.id + 1 = w2.id
where w1.Temperature < w2.Temperature
Post Reference: Vikram
Aristocratic Elfin Share
